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NEW QUESTION: 1
If x and y are positive integers (x>y), what is the units' digit of (10x - 9y)2 ?
A. 7.
B. 3.
C. 1.
D. 5.
E. 9.
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Try some numbers, x=2, y=1.
(106 - 92)2 = 81. And it will work with any given number under the conditions given.

NEW QUESTION: 2
A stateless session bean FooBean implements an asynchronous business method foo() on its bean class:
@Asynchronous
public void foo() ( ... )
The asynchronous business method is exposed through a remote business interface FooRemote. A caller acquires an EJB reference to this bean and invokes it as follows:
100. fooRemoteRef.foo();
Which exception can result from the invocation on line 100?
A. javax.ejb.EJBException
B. java.lang.IllegalArgumentException
C. java.rmi.RemoteException
D. java.util.concurrent.ExecutionException
Answer: C
Explanation:
Note:
*RemoteRef represents the handle for a remote object. A RemoteStub uses a remote reference to carry out a remote method invocation to a remote object.
*invoke
public Object invoke(Remote obj,
Method method,
Object[] params,
long opnum) throws Exception Invoke a method. This form of delegating method invocation to the reference allows the reference to take care of setting up the connection to the remote host, marshaling some representation for the method and parameters, then communicating the method invocation to the remote host. This method either returns the result of a method invocation on the remote object which resides on the remote host or throws a RemoteException if the call failed or an application-level exception if the remote invocation throws an exception. Parameters:

NEW QUESTION: 3
展示を参照してください。 EIGRPによって学習されたルートの要約を表すアドレスとマスクの組み合わせはどれですか？

A. 192.168.25.28 255.255.255.240
B. 192.168.25.0 255.255.255.240
C. 192.168.25.0 255.255.255.252
D. 192.168.25.16 255.255.255.240
E. 192.168.25.16 255.255.255.252
F. 192.168.25.28 255.255.255.252
Answer: D
Explanation:
20のバイナリバージョンは10100です。
16のバイナリバージョンは10000です。
24のバイナリバージョンは11000です。
28のバイナリバージョンは11100です。
サブネットマスクは/ 28です。マスクは255.255.255.240です。
注意：
上記の出力から、EIGRPは4つのルートを学習し、それらの要約を見つける必要があります。
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
->増分はbEでなければなりません。 28？16 = 12ですが、12は2のべき乗ではないため、選択する必要があります
16（24）。したがって、サブネットマスクは/ 28（= 1111 1111.1111 1111.1111 1111.11110000）=
255.255.255.240
したがって、最良の答えは192.168.25.16 255.255.255.240である必要があります