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NEW QUESTION: 1
Which log is used to see a failed NSX-T installation of a VIB package on ESXi transport nodes?
A. /var/l og/hostd. log
B. /var/log/vmware/eam/eam.log
C. /var/log/syslog.log
D. /var/log/esxupdate.log
Answer: C

NEW QUESTION: 2
DRAG DROP
As part of its upgrade to Windows 10 Enterprise, your company is implementing additional security controls relating to data access.
You need to implement a solution that meets the following requirements:
Which feature should you use to meet each requirement? To answer, drag the appropriate feature or features to the correct requirement or requirements. Each feature may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

NEW QUESTION: 3
Company plans to implement a new document management solution and move from optical storage to RAID5 storage. When they convert the document images from the optical platters to RAID5, how many pages will there be from a jukebox with ten 2.6GB platters, each of which 90% is full, assuming that average image size is 50KB?
A. 4,680,000 pages
B. 468,000 pages
C. 5,200,000 pages
D. 520,000 pages
Answer: B
Explanation:
2.6*1000000*10*0.9/50

NEW QUESTION: 4
Refer to the exhibit. Which address and mask combination represents a summary of the routes learned by EIGRP?

A. 192.168.25.16 255.255.255.240
B. 192.168.25.0 255.255.255.240
C. 192.168.25.28 255.255.255.252
D. 192.168.25.0 255.255.255.252
E. 192.168.25.28 255.255.255.240
F. 192.168.25.16 255.255.255.252
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
-> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24).
Therefore, the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240