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NEW QUESTION: 1
Click the Exhibit button to view the output of a FREQ procedure.
The variable STYLE has a permanent label of "Style of homes" and the variable
BEDROOMS has a permanent label of "Number of bedrooms".
Which one of the following SAS programs produced the output shown in the exhibit?

A. proc freq data = sasuser.houses;
tables style , bedrooms;
run;
B. proc freq data = sasuser.houses;
tables style;
tables bedrooms;
run;
C. proc freq data = sasuser.houses;
tables style * bedrooms;
run;
D. proc freq data = sasuser.houses;
tables style and bedrooms;
run;
Answer: B

NEW QUESTION: 2
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.1.0.0.0.0
B. 許可10.0.0.1.0.0.0.254
C. 許可10.0.0.0.0.0.0.1
D. 許可10.0.0.0.255.255.255.254
Answer: B
Explanation:
ワイルドカードマスクの場合、1はケアしない、0はケアすることを忘れないでください。それでは、簡単なACLを分析しましょう：
アクセスリスト1許可172.23.16.0 0.0.15.255
最初の2つのオクテットはすべて0です。これは、ネットワーク172.23.x.xに関心があることを意味します。ワイルドカードマスクの3番目のオクテット15（バイナリでは0000 1111）は、最初の4ビットは重要であるが最後の4ビットは重要ではないため、0001xxxxの形式で3番目のオクテットを許可することを意味します（最小：00010000 = 16 ;最大：0001111 = 31）。
4番目のオクテットは255（すべて1ビット）なので、気にしないでください。
したがって、ネットワーク172.23.16.0 0.0.15.255の範囲は172.23.16.0〜172.23.31.255です。
次に、ワイルドカードマスク0.0.0.254（4オクテット：254 = 1111 1110）を考えてみましょう。これは、最後のビットのみを気にすることを意味します。したがって、IPアドレスの最後のビットが「1」（0000 0001）の場合、奇数のみが許可されます。 IPアドレスの最後のビットが "0"（0000 0000）の場合、偶数のみが許可されます。
注：バイナリでは、奇数は常に「1」で終わりますが、偶数は常に「0」で終わります。
したがって、この質問では、「permit 10.0.0.1 0.0.0.254」というステートメントだけが、10.0.0.0 / 24サブネット内のすべての奇数番号のホストを許可します。

NEW QUESTION: 3
An engineeris troubleshooting non-802.11 interference and observes the shown output. Which interference signature is the most harmful to Wi-Fi?
Refer to the exhibit.

A. FHSS Bluetooth
B. analog videocamera
C. microwave oven
D. 2 4 GHz wideband jammer
E. cordless phone
Answer: E

NEW QUESTION: 4
Civil law countries rely solely on statues, are called ________, to regulate their contractual relations.
A. Facts
B. Conducts
C. Codes
D. Constraints
Answer: C