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NEW QUESTION: 1
Refer to the exhibit.

Which statement is true?
A. IS-IS has been enabled on R4 for IPv6, single-topology.
B. IS-IS has been enabled on R4 for IPv6, multitopology.
C. IS-IS has been enabled on R4 for IPv6, single-topology and multitopology.
D. R4 advertises IPv6 prefixes, but it does not forward IPv6 traffic, because the protocol has not been enabled under router IS-IS.
Answer: A
Explanation:
When working with IPv6 prefixes in IS-IS, you can configure IS-IS to be in a single topology for both IPv4 and IPv6 or to run different topologies for IPv4 and IPv6.
By default, IS-IS works in single-topology mode when activating IPv4 and IPv6. This means that the IS-IS topology will be built based on IS Reachability TLVs. When the base topology is built, then IPv4 prefixes (IP Reachability TLV) and
IPv6 prefixes (IPv6 Reachability TLV) are added to each node as leaves, without checking if there is IPv6 connectivity between nodes.
Reference: https://blog.initialdraft.com/archives/3381/

NEW QUESTION: 2
Which of the following algorithms has well documented collisions? (Select TWO).
A. MD5
B. SHA-256
C. SHA
D. RSA
E. AES
Answer: A,C
Explanation:
B: MD5 biggest weakness is that it does not have strong collision resistance, and thus it is no longer recommended for use.
C: SHA-1 (also known as SHA) is being retired from most government uses; the U.S. National Institute of Standards and Technology said, "Federal agencies should stop using SHA-1 for...applications that require collision resistance as soon as practical, and must use the SHA-2 family of hash functions for these applications after 2010", though that was later relaxed. Note: The hashing algorithm must have few or no collisions. This means that hashing two different inputs does not give the same output. Cryptographic hash functions are usually designed to be collision resistant. But many hash functions that were once thought to be collision resistant were later broken. MD5 and SHA-1 in particular both have published techniques more efficient than brute force for finding collisions.

NEW QUESTION: 3
Which of the following statements will create an application-period temporal table?
A. CREATE TABLE POLICY_ATT(BANK VARCHAR(4),
BUS_BEGIN TIMESTAMP NOT NULL, BUS_END TIMESTAMP NOT NUK, CLIENT CHAR{4), TYPE CHAR(5), PAY INT. PERIOD BUSINESS_TIME(BUS_BEGIN. BUS_END));
B. CREATE TABLE POLICY_ATT(BANK VARCHAR(4). BUS_BEGIN TIMESTAMP. BUS_END TIMESTAMP.
CLIENT CHAR(4), TYPE CHAR(5), PAY INT. PERIOD BUSINESS_TIME(BUS_BEGIN. BUS_END));
C. CREATE TABLE POLICY_ATT(BANK VARCHAR(4). SYS_BEGIN TIMESTAMP. SYS_END TIMESTAMP, CLIENT CHAR(4), TYPE CHAR(5), PAY INT, PERIOD SYSTEM_TIME(SYS_BEGIN, SYS_END));
D. CREATE TABLE POLICY_ATT(BANK VARCHAR(4),
SYS_BEGIN TIMESTAMP NOT NULL, SYS_END TIMESTAMP NOT NULL, CLIENT CHAR(4)T TYPE CHAR(5), PAY INT, PERIOD SYSTEM_TIME(SYS_BEG1N, SYS_END));
Answer: B