NCP-DB Practice Questions

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NEW QUESTION: 1
Given the code fragment:
Path source = Paths.get ("/data/december/log.txt");
Path destination = Paths.get("/data");
Files.copy (source, destination);
and assuming that the file /data/december/log.txtis accessible and contains:
10-Dec-2014 - Executed successfully
What is the result?
A. A FileNotFoundExceptionis thrown at run time.
B. A FileAlreadyExistsExceptionis thrown at run time.
C. A file with the name log.txtis created in the /datadirectory and the content of the /data/
december/log.txtfile is copied to it.
D. The program executes successfully and does NOT change the file system.
Answer: B

NEW QUESTION: 2
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.1.0.0.0.254
B. Permit 10.0.0.0.255.255.255.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: A
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 3
Scenario 2:
After completing the branch activation activities for all required branches, the administrator attempts to test connectivity between the various branches and between the hubs and branches- The administrator notices a lack of connectivity despite being certain that configurations have been complete. The administrator also observed that several users are reporting intermittent connectivity to some of the applications they are accessing. Other users are reporting no access to these applications. Other users at some of the branches claim they cannot get to certain public resources. The administrator wants to ensure that all sites can talk to each other and all resources are accessible.
Exhibit.

The tunnel from the Dallas site to the Seattle hub is not coming up.
What are two things that should be checked to determine the issue? (Choose two.)
A. Spoke Edge and Hub Edge have a mismatched certificate.
B. Dynamic Branch to Branch is not enabled.
C. Hub WAN Interface might be behind a firewall.
D. Spoke Edge and Hub Edge are two different Edge models.
Answer: A,D

NEW QUESTION: 4

Select and Place:

Answer:
Explanation:

Explanation:
Put is a correct answer, however if PUT is missing as an option, POST could also be valid if you consider "id" to be a parameter.