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NEW QUESTION: 1
You work as the database administrator for your company. A SQL Server 2005 database is utilized to have online sales tracked. It is reported by employees who run the In-Stock that they are experiencing slow performance. After detailed analysis, you find that the contention between the In-Stock report and high volume of data entry to the tables that are accessed in this report causes the performance problem. The company intends to have the In-Stock report returned instantly even though the data might be changed by other employees within their data-entry transactions. The employees who are running the In-Stock report should be able to see any changes which are made in other transactions when the report is running.
Since you are the database administrator, you are required to implement a solution to accomplish this task. Which action should be performed?
A. The transaction isolation level should be modified for the report transaction to serializable.
B. The transaction isolation level should be modified for the report transaction to Read Uncommitted.
C. The database should be set to enable the Read Committed snapshot option.
D. The transaction isolation level should be modified for the report transaction to snapshot.
Answer: B

NEW QUESTION: 2
Which command in ASA allows ASDM connection from client PC over https with the Local AAA user database?
A. aaa authentication Telnet console LOCAL
B. aaa authentication ssh console LOCAL
C. aaa authentication http console LOCAL
D. aaa authentication enable console LOCAL
Answer: C

NEW QUESTION: 3
내부 감사가 적법한 전문가를 위해 취해야 할 다음 조치 중
케어?
1. 각 감사 업무에서 중대한 비준수 가능성을 고려하십시오.
2. 이익 대비 보증 비용을 측정합니다.
3. 모든 위험을 식별 할 수 있도록 충분한 주의를 기울여 보증 절차를 수행하십시오.
A. 1과 3 만
B. 1과 2 만
C. 2와 3 만
D. 1,2 및 3
Answer: B

NEW QUESTION: 4

A. 10.1.160.255
B. 10.1.160.0
C. 10.1.174.255
D. 10.1.168.0
E. 10.1.176.1
F. 10.1.175.255
Answer: A,C,D
Explanation:
All IP address in IP ranges between: 10.1.160.1 and 10.1.175.254 are valid as shown below Address: 10.1.160.0 00001010.00000001.1010 0000.00000000 Netmask:255.255.240.0 = 2011111111.11111111.1111 0000.00000000 Wildcard:0.0.15.25500000000.00000000.0000 1111.11111111
Which implies that: Network: 10.1.160.0/20 00001010.00000001.1010 0000.00000000 HostMin:10.1.160.100001010.00000001.1010 0000.00000001 HostMax:10.1.175.25400001010.00000001.1010 1111.11111110 Broadcast:10.1.175.25500001010.00000001.1010 1111.11111111