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NEW QUESTION: 1
You have a server named Serverl that runs Windows Server 2012 R2.
You try to install the Microsoft .NET Framework 3.5 Features feature on Server1, but the
installation fails repeatedly.
You need to ensure that the feature can be installed on Serverl.
What should you do?
A. Remove the .NET Framework 4.5 Features feature.
B. Run the Add-AppxProvisionedPackage cmdlet.
C. Disable User Account Control (UAC).
D. Connect Serverl to the Internet.
Answer: D

NEW QUESTION: 2
You have a Cisco Unified Border Element configured to provide H.323 to SIP interworking. Which command will verify that you have a single H.323 and a single SIP call leg when the call is placed?
A. show dialpeer voice
B. debug voice dialpeer
C. debug voip ipipgw
D. show call active voice
Answer: D
Explanation:
The show call active voice command allows you to display the contents of the active call table. The show call active voice command displays data from the plain old telephone service (POTS) and VoIP call legs on the voice gateway. The information presented includes call times, dial peers, connections, quality of service parameters, and gateway handling of jitter. This information can be useful when you troubleshoot a range of voice quality problems.
http://www.cisco.com/en/US/docs/ios/voice/cube/configuration/guide/vb-gwh323sip.html#wp1342172

NEW QUESTION: 3
Refer to the exhibit. What two results would occur if the hub were to be replaced with a switch that is configured with one Ethernet VLAN? (Choose two.)

A. The number of broadcast domains would remain the same.
B. The number of collision domains would increase.
C. The number of collision domains would remain the same.
D. The number of collision domains would decrease.
E. The number of broadcast domains would decrease.
F. The number of broadcast domains would increase.
Answer: A,B
Explanation:
Basically, a collision domain is a network segment that allows normal network traffic to flow back and forth. In the old days of hubs, this meant you had a lot of collisions, and the old CSMA/CD would be working overtime to try to get those packets re-sent every time there was a collision on the wire (since ethernet allows only one host to be transmitting at once without there being a traffic jam). With switches, you break up collision domains by switching packets bound for other collision domains. These days, since we mostly use switches to connect computers to the network, you generally have one collision domain to a PC.
Broadcast domains are exactly what they imply: they are network segments that allow broadcasts to be sent across them. Since switches and bridges allow for broadcast traffic to go unswitched, broadcasts can traverse collision domains freely. Routers, however, don't allow broadcasts through by default, so when a broadcast hits a router (or the perimeter of a VLAN), it doesn't get forwarded. The simple way to look at it is this way: switches break up collision domains, while routers (and VLANs) break up collision domains and broadcast domains. Also, a broadcast domain can contain multiple collision domains, but a collision domain can never have more than one broadcast domain associated with it.
Collision Domain: A group of Ethernet or Fast Ethernet devices in a CSMA/CD LAN that are connected by repeaters and compete for access on the network. Only one device in the collision domain may transmit at any one time, and the other devices in the domain listen to the network in order to avoid data collisions. A collision domain is sometimes referred to as an Ethernet segment.
Broadcast Domain: Broadcasting sends a message to everyone on the local network (subnet). An example for Broadcasting would be DHCP Request from a Client PC. The Client is asking for a IP Address, but the client does not know how to reach the DHCP Server. So the client sends a DHCP Discover packet to EVERY PC in the local subnet (Broadcast). But only the DHCP Server will answer to the Request.
How to count them?
Broadcast Domain: No matter how many hosts or devices are connected together, if they are connected with a repeater, hub, switch or bridge, all these devices are in ONE Broadcast domain (assuming a
single VLAN). A Router is used to separate Broadcast-Domains (we could also call them Subnets
- or call them VLANs).
So, if a router stands between all these devices, we have TWO broadcast domains.
Collision Domain:
Each connection from a single PC to a Layer 2 switch is ONE Collision domain. For example, if 5
PCs are connected with separate cables to a switch, we have 5 Collision domains. If this switch is
connected to another switch or a router, we have one collision domain more.
If 5 Devices are connected to a Hub, this is ONE Collision Domain. Each device that is connected
to a Layer 1 device (repeater, hub) will reside in ONE single collision domain.

NEW QUESTION: 4
An LTM has the 3 virtual servers, 2 SNATs, four self IP addresses defined and the networks shown in the exhibit. Selected options for each object are shown below. Settings not shown are at their defaults.
Assume port exhaustion has not been reached. VirtualServerl Destination: 10.10.2.102:80 netmask 255.255.255.255 Pool: Pool with 3 members in the 172.1 61.16 network SNAT Automap configured V VirtualServer2 Destination: 10.10.2.102:* netmask
255.255.255.255 Transparent with 3 pool members
in the 192.168/16 network VirtualServer3 Destination: 10.10.2.0:80 netmask 255.255.255.0 Type: IP Forwarding SNATI Source IP: 10.10.0.0 netmask 255.255.0.0 SNAT Address: SNAT Pool with 2 members
172.16.20.50 and 192.168.10.50 SNAT2 Source IP: All Addresses SNAT Address: 10.10.2.103 Floating Self IPs 192.168.1.1; 172.16.1.1; 10.10.2.1; 10.10.1.1 A connection attempt is made with a source IP and port of 10.20.100.50:2222 and a destination IP and port of 10.10.2.102:443. When the request is processed, what will be the source and destination IP addresses?

A. Source IP: 10.10.201; Destination IP: 10.102.102
B. Source IP: 10.20.10.50; Destination IP: pool member in the 192.168/16 network
C. Source IP: 10.10.2.103; Destination IP: 10.10.2.102
D. Source IP: 10.10.2.103; Destination IP: pool member in the 192.168/16 network
E. Source IP: 10.10.201; Destination IP: pool member in the 192.168/16 network G
F. The request will be dropped.
Answer: C