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NEW QUESTION: 1
Provisional training is provided for a project that is in the process of client hand-over. The client then asks for a step-by-step manual which was not included in the project's deliverables What should the project manager do?
A. Accept the request and have the learn immediately begin work on the manual
B. Initiate the change control process
C. Reject the request because it is out of scope
D. Offer to develop the manual as a separate project
Answer: D

NEW QUESTION: 2
You have 100 computers that run Windows 8.1 and are enrolled in Upgrade Readiness.
Two of the computers are configured as shown in the following table.

From Upgrade Readiness, you view the applications shown in the following table.

You enroll a computer named Computer3 in Upgrade Readiness. Computer3 has the following configurations:
* 8 GB of memory
* 64-bit architecture
* An application named App3 installed
App3 is installed on Computer3 only.
For each of the following statements, select Yes if the statement is true. Otherwise, select No.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

NEW QUESTION: 3

A. Option A
B. Option B
C. Option D
D. Option C
Answer: C

NEW QUESTION: 4
Which single Cisco IOS ACL entry permits IP addresses from 172.16.80.0 to 172.16.87.255?
A. permit 172.16.80.0 0.0.248.255
B. permit 172.16.80.0 0.0.3.255
C. permit 172.16.80.0 0.0.7.255
D. permit 176.16.80.0 255.255.252.0
E. permit 172.16.80.0 255.255.240.0
F. permit 172.16.80.0 255.255.248.0
Answer: C
Explanation:
www.cisco.com/en/US/products/sw/secursw/ps1018/products_tech_note09186a00800a5b9a.shtm
ACL Summarization NotE. Subnet masks can also be represented as a fixed length notation. For example, 192.168.10.0/24 represents 192.168.10.0 255.255.255.0. This list describes how to summarize a range of networks into a single network for ACL optimization. Consider these networks. 192.168.32.0/24 192.168.33.0/24 192.168.34.0/24 192.168.35.0/24 192.168.36.0/24 192.168.37.0/24 192.168.38.0/24 192.168.39.0/24
The first two octets and the last octet are the same for each network. This table is an explanation of how to summarize these into a single network.
The third octet for the previous networks can be written as seen in this table, according to the octet bit position and address value for each bit.
Decimal 128 64 32 16 8 4 2 1 32 0 0 1 0 0 0 0 0 33 0 0 1 0 0 0 0 1 34 0 0 1 0 0 0 1 0 35 0 0 1 0 0 0 1 1 36 0 0 1 0 0 1 0 0 37 0 0 1 0 0 1 0 1 38 0 0 1 0 0 1 1 0 39 0 0 1 0 0 1 1 1 M M M M M D D D
Since the first five bits match, the previous eight networks can be summarized into one network (192.168.32.0/21 or 192.168.32.0 255.255.248.0). All eight possible combinations of the three low-order bits are relevant for the network ranges in question. This command defines an ACL that permits this network. If you subtract 255.255.248.0 (normal mask) from 255.255.255.255, it yields
0.0.7.255.
access-list acl_permit permit ip 192.168.32.0 0.0.7.255