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NEW QUESTION: 1
Welche Schlussfolgerung ist in Bezug auf das hier gezeigte experimentelle Design mit der Antwort in der Spalte ganz rechts am zutreffendsten?
A. Dieses Design verfügt nicht über genügend experimentelle Läufe, um auf etwas zu schließen, was durch das Fehlen von P-Werten in der MINITABTM-Ausgabe belegt wird
B. Wenn der Adv vom niedrigen auf den hohen Pegel erhöht wird, erhöht sich die Antwortrate
C. Kein Faktor hat ein ausreichendes statistisches Vertrauen von mehr als 95%, um einen Einfluss auf die Rücklaufquote zu haben
D. Konstante, Adv und Bev sind die einzigen Faktoren, die die Rücklaufquote mit 95% igem Vertrauen oder mehr statistisch beeinflussen
E. Es wird statistisch festgestellt, dass das Antwortniveau nur die auf dem niedrigen Niveau eingestellten Adv- und Bev-Faktoren benötigt, um die größte Antwortrate zu erhalten
Answer: E

NEW QUESTION: 2





A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
C. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
D. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
F. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
H. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
Answer: D

NEW QUESTION: 3
You are developing an application for use by meteorologists. Form1 contains a list item based on a query of cloud types that are stored in a database table. Users can add cloud types to the list by typing in new values that are automatically inserted to the database table. Form1 calls Form2, which contains an identical list item. You do not want to requery the database to obtain the list of cloud types. Which method can you use to pass the cloud types from Form1 to Form2?
A. Global variables
B. Parameter list
C. Shared PL/SQL library
D. Global record group
E. There is no way to pass such data between forms; you must requery the data from the database.
Answer: D

NEW QUESTION: 4
無料枠を超えた後、AWSはAWS Lambdaの使用に対してどのように課金しますか？ （2つ選択）
A. Lambda関数の実行にかかる時間まで。
B. 特定のLambda関数に対して行われたリクエストの数。
C. Lambda関数に使用されるプログラミング言語による
D. AWSアカウントのLambda関数の総数
E. 特定のLambda関数のバージョンの数。
Answer: A,B