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NEW QUESTION: 1
You are a technical consultant designing a solution for an online retail company. The project vision is to deploy a hybrid cloud, with the internal team developing the website on internal infrastructure and migrating production-ready applications to a hosting provider. The project is expected to ease deployment and require less infrastructure capital expenditure-without lowering application quality.
Which of the following is a risk to the project?
A. The applications to be deployed on the production hosts are not fully developed, although a beta exists.
B. Change control of the hosting vCloud platform is not under full control of the internal business.
C. The hosting provider outsources the platform support to the platform vendor.
D. The solution must adhere to ISO 27001.
Answer: B
Explanation:
The technical design process enables the platform designer to work in a methodical way and withothers who have similar objectives. A risk is that a project item could potentially prevent the vision or aspectsof it (requirements) from being created. Chapter 1, The Technical Design Process

NEW QUESTION: 2
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:

Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: D
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1

NEW QUESTION: 3
Male with urinary incontinence. Sling procedure was performed 6 months ago and now the patient has returned for a revision of the sling procedure.
A. 0
B. 1
C. 2
D. 3
Answer: D