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NEW QUESTION: 1

A. Option A
B. Option C
C. Option B
D. Option D
Answer: D
Explanation:
AWS is introducing a free usage tier for one year to help the new AWS customers get started in Cloud.
The free tier can be used for anything that the user wants to run in the Cloud. AWS offers a handful of
AWS services as a part of this which includes 750 hours of free micro instances and 750 hours of ELB. It
includes the AWS S3 of 5 GB and AWS EBS general purpose volume upto 30 GB. PIOPS is not part of
free usage tier.
Reference: http://aws.amazon.com/free/

NEW QUESTION: 2
대규모 전자 상거래 사이트는 Amazon S3에서 정적 객체를 제공하도록 설계되었습니다. Amazon S3 버킷은 초당 300 회 이상의 GET 요청을 서버에 전달합니다. 성능을 최적화하려면 어떻게 해야 합니까? (2 개 선택)
A. Integrate Amazon CloudFront with Amazon S3.
B. Configure Amazon S3 lifecycle rules.
C. Enable Amazon S3 cross-region replication.
D. Delete expired Amazon S3 server log files.
E. Randomize Amazon S3 key name prefixes.
Answer: A,E
Explanation:
Explanation
CloudWatch definitely. Random key prefixes is still a valid method of improving performance by using parallel reads. It doesn't mention prefix hashing. For instance prefixes 1/,2/,3/,4,5/ could provide 5 x parallel streams for S3 as opposed to all objects being in a single folder/prefix e.g. dev/
https://docs.aws.amazon.com/AmazonS3/latest/dev/optimizing-performance.html
"There are no limits to the number of prefixes in a bucket. You can increase your read or write performance by parallelizing reads. For example, if you create 10 prefixes in an Amazon S3 bucket to parallelize reads, you could scale your read performance to 55,000 read requests per second." The assumption that prefixes don't matter is incorrect, as described by "Amazon S3 performance guidelines recommended randomizing prefix naming with **hashed characters** to optimize performance for frequent data retrievals. You no longer have to randomize prefix naming for performance, and can use sequential date-based naming for your prefixes"

NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
const char *s;
char str[] = "Hello";
s = str;
while(*s) {
cout << *s++;
}
return 0;
}
A. It prints: Hello
B. It prints: el
C. It prints: H
D. It prints: o
Answer: A