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NEW QUESTION: 1
Drag and drop the BGP attribute on the left to the correct category on the right. Not all options will be used.

Answer:
Explanation:

Explanation
BGP Well-known Mandatory Attribute
V AS_Path
BGP Optional Nontransitive Attribute
Cluster List
Originator ID
BGP Optional Transitive Attributes
Community

NEW QUESTION: 2
You use SQL Server 2014 Enterprise Edition.
Your database contains a partitioned table named AuditData. AuditData is partitioned by year. Partition 1 contains data from the year 2010 and prior.
Management has decided to archive all AUDITDATA records from 2010 and prior.
Management wants the records to be removed from the database entirely and provided to the backup team as a zipped text file. The data must no longer reside in the database.
There is very little tolerance for performance degradation in your environment. You need to remove all 2010 and prior data from the AuditData table by using the least amount of system resources possible. Develop the solution by selecting and arranging the required SQL actions in the correct order.
You may not need all of the actions.

Answer:
Explanation:

Explanation

Note:
- Create a new partitioned table with the partition function you want, and then insert the data from the old table into the new table by using an INSERT INTO...SELECT FROM statement.
- SPLIT RANGE ( boundary_value )
Adds one partition to the partition function. boundary_value determines the range of the new partition, and must differ from the existing boundary ranges of the partition function. Based on boundary_value, the Database Engine splits one of the existing ranges into two.
Of these two, the one where the new boundary_value resides is considered the new partition.
- BCP can be used top produce the zipped text file.
- Example: plitting a partition of a partitioned table or index into two partitions The following example creates a partition function to partition a table or index into four partitions.
ALTER PARTITION FUNCTION splits one of the partitions into two to create a total of five partitions.
CREATE PARTITION FUNCTION myRangePF1 (int)
AS RANGE LEFT FOR VALUES ( 1, 100, 1000 );
GO
-Split the partition between boundary_values 100 and 1000
-to create two partitions between boundary_values 100 and 500
--and between boundary_values 500 and 1000.
ALTER PARTITION FUNCTION myRangePF1 ()
SPLIT RANGE (500);

NEW QUESTION: 3
A network administrator has configured the network on each floor of a four-story building to have the following different subnets: 10.0.10.0/24, 127.0.0.0/24, 172.16.0.0/24, and 192.168.255.0/24. After implementing these networks, the administrator realizes there has been a mistake. Which of the following BEST describes the mistake?
A. 192.168.255.0/24 is not valid because 255 in the third octet cannot be used in the network portion of the IP address.
B. 127.0.0.0/24 is the reserved loopback network and cannot be used for host networks.
C. 10.0.10.0/24 is not valid because 0 in the second octet cannot be used in the network portion of the IP address.
D. 172.16.0.0/24 is the reserved multicast network and cannot be used for host networks.
Answer: B