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NEW QUESTION: 1
For which type of connection is broadband PPPoE most appropriate?
A. GRE tunnel
B. satellite
C. DSL
D. PPTP
Answer: C

NEW QUESTION: 2
사용자는 아래와 같이 트래픽을 허용하는 두 개의 보안 그룹을 구성했습니다. 1 : SecGrp1 :
0.0.0.0/0의 경우 포트 80의 인바운드 0.0.0.0/0의 경우 포트 22의 인바운드 2 : SecGrp2 :
10.10.10.1/32의 포트 22 인바운드
두 보안 그룹이 동일한 인스턴스와 연관된 경우, 다음 중 어느 것이 맞습니까?
A. 단일 인스턴스에 둘 이상의 보안 그룹을 할당 할 수 없습니다
B. 규칙이 충돌하는 보안 그룹을 만들 수 없습니다. AWS는 요청을 거부합니다
C. 포트 22와 80 모두에서 인바운드 트래픽을 허용합니다.
D. IP 10.10.10.1의 경우 포트 22에서 인바운드 트래픽을 허용하고 포트 80의 다른 모든 사용자에게 허용
Answer: C
Explanation:
설명
사용자는 단일 EC2 인스턴스에 둘 이상의 보안 그룹을 연결할 수 있습니다. 이 경우 각 보안 그룹의 규칙이 효과적으로 집계되어 하나의 규칙 집합을 만듭니다. AWS는이 규칙 집합을 사용하여 액세스 허용 여부를 결정합니다. 따라서 여기서 IP 10.10.10.1/32의 포트 22에 대한 규칙은 IP와 병합됩니다.
0.0.0.0/0 및 모두 포트 22 및 80을 엽니 다.
http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/using-network-security.html

NEW QUESTION: 3
You are developing a new version of an existing message contract named CustomerDetailsVersion1.
The new version of the message contract must add a Department field of type String to the SOAP header.
You create a new class named CustomerDetailsVersion2 that inherits from CustomerDetailsVersion1.
You need to ensure that all client applications can consume the service.
Which code segment should you use?
A. Public Class CustomerDetailsVersion2 Inherits CustomerDetailsVersionl <MessageHeader(MustUnderstand:=True)> Public Department As String End Class
B. Public Class CustomerDetailsVersion2 Inherits CustomerDetailsVersionl <MessageHeader(HustUnderstand:=False) > Public Department As String End Class
C. <MessageContract() > Public Class CustomerDetailsVersion2 Inherits CustomerDetailsVersionl <MessageHeader(HustUnderstand:=False)> Public Department As String End Class
D. <MessageContract()> Public Class CustomerDetailsVersion2 Inherits CustomerDetailsVersionl <MessageHeader(HustUnderstand:=True)> Public Department As String End Class
E. Public Class CustomerDetailsVersion2 Inherits CustomerDetailsVersionl <MessageHeader(HustUnderstond:"True)> Public Department As String End Class
Answer: C