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NEW QUESTION: 1
What are the general steps to creating a tenant with Cisco ASA services?
A. Create the tenant, apply the graph to the contract subject, define the Layer 4 to Layer 7 service device cluster, define the logical device content, create the service graph.
B. Click the Create ASA Services button in the Cisco APIC Management Interface and enter the appropriate text and information.
C. You should not create the Cisco ASA Services as a tenant; it should be created as a bridge domain.
D. Create the tenant, define the Layer 4 to Layer 7 service device cluster, create the service graph, define the logical device content, apply the graph to the contract subject.
Answer: D

NEW QUESTION: 2





A. Option A
B. Option D
C. Option C
D. Option B
Answer: B
Explanation:
References: https://docs.microsoft.com/en-us/sql/t-sql/queries/contains-transact- sql?view=sql-server-2017

NEW QUESTION: 3
The following data have been extracted from the financial statements of a firm for two years, 1991 and
1992:
1991 1992
Assets 9,947 9,682
Sales 11,035 10,377
Current liabilities 4,193 3,920
Non-current liabilities 3,827 3,476
The asset turnover and the equity turnover for 1992 equal ________.
A. 0.98, 2.56
B. 2.11, 3.92
C. 1.06, 4.93
D. 1.34, 6.38
Answer: C
Explanation:
Explanation/Reference:
Explanation:
Total asset turnover = net sales/average total assets
Total equity turnover = net sales/average equity
The total liabilities in 1991 = 4,193 + 3,827 = 8,020 and total liabilities in 1992 = 3,920 + 3,476 = 7,396.
Therefore, using the equation,
Total Assets = Total Liabilities + Total Equity,
the equity in 1991 was 9,947 - 8020 = 1,927 and in 1992, it was 9,682 - 7,396 = 2,286. Thus, the average equity for 1992 equals (1,927 + 2,286)/2 = 2,107 and average assets for 1992 equal (9,682 + 9,947)/2
9,815. Therefore, asset turnover for 1992 = 10,377/9,815 = 1.06 and equity turnover = 10,377/2,107
4.93.

NEW QUESTION: 4
Given the code fragment:

What is the result?
A. [1, 3, 4, null]
B. Compilation fails.
C. A NullPointerException is thrown at runtime.
D. [1, 2, 4]
E. [1, 3, 4]
F. [1, 2, 4, null]
Answer: D