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NEW QUESTION: 1
What is a class? (No Answer)
A. Database class method
B. Ajax toolkit, client program
C. Apex, Visualforce, and APIs
D. A template from which objects are created
Answer: D

NEW QUESTION: 2
A collaboration engineer is troubleshooting an MOH problem on a Cisco IOS SIP gateway in searching through a debug CCSIP massage output. Which three parameters in the SIP massages can be used to determine if the call was placed on hold? (Choose three)
A. INVITE WITH a=SENDONLY
B. BYE WITH A = CALLHOLD
C. c=IN IP4 0.0.0.0
D. INVITE WITH a=INACTIVE
E. OPTIONS WITH 301 CALLHOLD
F. OPTION WITH c=INACTIVE
Answer: A,C,D

NEW QUESTION: 3
See the Exhibit and examine the structure of the PROMOTIONS table:
Exhibit:

Using the PROMOTIONS table, you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:
Exhibit:

What would be the outcome?
A. It generates an error because CASE cannot be used with group functions
B. It generates an error because NULL cannot be specified as a return value
C. It generates an error because multiple conditions cannot be specified for the WHEN clause
D. It executes successfully and gives the required result
Answer: D
Explanation:
Explanation/Reference:
Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an
IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END

NEW QUESTION: 4
View the Exhibit and examine the structure of the CUSTOMERS table .Which statement would display the highest credit limit available in each income level in each city in the CUSTOMERS table?

A. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_city, cust_income_level;
B. SELECT cust_city, cust_income_level, MAX(cust_credit_limit ) FROM customers GROUP BY cust_city, cust_income_level, cust_credit_limit;
C. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_credit_limit, cust_income_level, cust_city ;
D. SELECT cust_city, cust_income_level, MAX(cust_credit_limit) FROM customers GROUP BY cust_city, cust_income_level, MAX(cust_credit_limit);
Answer: A