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NEW QUESTION: 1
In a SQL Procedure, rows_fetched is an integer variable and curEmp is a cursor variable of SELECT statement on a table. After opening the cursor curemp, which of the statement will determine the number of rows fetched?
A. SET rows_fetched = curEmp%CURSOR_ROWCOUNT
B. SET rows_fetched = CURSOR_ROWCOUNT(curemp)
C. SET rows_fetched = ROWCOUNT(curemp)
D. SET rows_fetched = curEmp%ROWCOUNT
Answer: B

NEW QUESTION: 2
ネットワークにcontoso.comという名前のActive Directoryドメインが含まれています。 フォレストとドメインの機能レベルはWindows Server 2008 R2です。 ドメイン内のすべてのサーバーは、Windows Server 2016標準を実行しています。 ドメインには、Windows 8.1またはWindows 10のいずれかを実行している100台のクライアントコンピュータが含まれています。
ドメインには、次の表に示すように構成されている9台のサーバーが含まれています。


Answer:
Explanation:

NEW QUESTION: 3
Given the code fragment:
System.out.printIn("Result: " + 2 + 3 + 5);
System.out.printIn("Result: " + 2 + 3 * 5);
What is the result?
A. Result: 10
Result: 25
B. Compilation fails
C. Result: 215
Result: 215
D. Result: 10
Result: 30
E. Result: 235
Result: 215
Answer: E
Explanation:
Explanation/Reference:
Explanation:
First line:
System.out.println("Result: " + 2 + 3 + 5);
String concatenation is produced.
Second line:
System.out.println("Result: " + 2 + 3 * 5);
3*5 is calculated to 15 and is appended to string 2. Result 215.
The output is:
Result: 235
Result: 215
Note #1:
To produce an arithmetic result, the following code would have to be used:
System.out.println("Result: " + (2 + 3 + 5));
System.out.println("Result: " + (2 + 1 * 5));
run:
Result: 10
Result: 7
Note #2:
If the code was as follows:
System.out.println("Result: " + 2 + 3 + 5");
System.out.println("Result: " + 2 + 1 * 5");
The compilation would fail. There is an unclosed string literal, 5", on each line.