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NEW QUESTION: 1
Which two are types of network virtualization? (Choose two.)
A. VSS: Virtual Switching System
B. VLSM: variable length subnet masking
C. VM: virtual machine
D. VCI: virtual channel identifier
E. VMP: Virtual Memory Pool
F. VRF: virtual routing and forwarding
Answer: A,F
Explanation:
Network virtualization encompasses logical isolated network segments that share the same
physical infrastructure. Each segment operates independently and is logically separate
from the other segments. Each network segment appears with its own privacy, security,
independent set of policies, QoS levels, and independent routing paths.
Here are some examples of network virtualization technologies:
VLAN: Virtual local-area network
VSAN: Virtual storage-area network
VRF: Virtual routing and forwarding
VPN: Virtual private network
VPC: Virtual Port Channel

NEW QUESTION: 2
DRAG DROP
Your company has a private cloud that is managed by using a System Center 2012
infrastructure.
The private cloud contains 200 servers that run Windows Server 2008 R2. All of the
servers are managed by Operations Manager.
The private cloud contains an application named App1 that is deployed on-demand to several servers. The servers that run the application are identified by a registry value set during the application's installation.
You create a monitor that targets all of the servers.
You need to modify the monitor to only affect the servers that have the application installed.
Which three actions should you perform in sequence? (To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.)

Answer:
Explanation:

NEW QUESTION: 3
You need an algorithm that must:
Iterate through an array of primitive integers
Print the value of each array element in index order
If the value of the element is equal to 10, print the value of the element, and then terminate the iteration
Which method correctly implements the algorithm?
A. public static void foo(int[] list) {
for(int i=0; i < list.length; i++) {
System.out.println(i);
if (i==10) continue;
}
B. public static void foo(int[] list) {
for each(int i in list) {
System.out.println(i);
if (i==10) terminate;
}
C. public static void foo(int[] list) {
while(list.length > 0) {
System.out.println(i);
if (i==10) break;
}
D. public static void foo(int[] list) {
for(int i=0; i < list.length; i++) {
System.out.println(i);
if (i==10) break;
}
E. public static void foo(int[] list) {
for(int i:list) {
System.out.println(i);
if (i==10) break;
}
Answer: E