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NEW QUESTION: 1
注：この質問は、同じシナリオを使用する一連の質問の一部です。あなたの便宜のために、シナリオは各質問で繰り返されます。各質問は異なる目標と答えの選択を提示しますが、シナリオのテキストはこのシリーズの各質問でまったく同じです。
BlogCategory、BlogEntry、ProductReview、Product、およびSalesPersonの各テーブルを含むデータベースがあります。テーブルは、次のTransact SQLステートメントを使用して作成されました。

以下の要件を満たすようにProductReviewテーブルを変更する必要があります。
* テーブルはProductテーブルのProductID列を参照する必要があります
* ProductReviewテーブル内の既存のレコードは、Productテーブルで検証してはいけません。
* レコードがProductReviewテーブルによって参照されている場合は、Productテーブルのレコードを削除してはいけません。
* Productテーブルのレコードへの変更はProductReviewテーブルに伝播する必要があります。
次のデータベーステーブルもあります：Order、ProductTypes、およびSalesHistory、これらのテーブルのtransaction-SQLステートメントは使用できません。
以下の要件を満たすようにOrdersテーブルを変更する必要があります。
* テーブルにINSERT権限を付与せずにテーブルに新しい行を作成します。
* 注文が完了したかどうかを注文を出した販売員に通知してください。
SalesHistoryテーブルに次の制約を追加する必要があります。
* フィールドをレコードIDとして使用できるようにするSaleID列の制約
* ProductTypesテーブルのProduct列を参照するためにProductID列を使用する定数
* 列にNULL値を持つ1行を許可するCategoryID列に対する制約
* SalesPrice列を4人以上の財務部門のユーザーの値に制限する制約は、SalesYTD列の値が特定のしきい値を超える営業担当者のSalesHistoryテーブルからデータを取得できる必要があります。
SalesOrderという名前のメモリ最適化テーブルを作成する予定です。テーブルは以下の要件を満たす必要があります。
* テーブルには1000万のユニークな受注がなければなりません。
* テーブルは、入出力操作を最小限に抑えるためにチェックポイントを使用しなければならず、トランザクションロギングを使用してはいけません。
* データ損失は許容範囲内です。
完全等価操作を使用してWhere句を使用するSalesOrderテーブルに対するクエリのパフォーマンスを最適化する必要があります。
ProductReviewテーブルの参照整合性を有効にする必要があります。
関連するTransact-SQLステートメントをどのように完成させるべきですか？答える？回答領域で適切なTransact-SQLセグメントを選択します。
2つの選択肢を選択してください。
A. 最初の選択では、WITH NOCHECKを選択します。
B. 2番目の選択では、[CASCADEを削除]と[CASCADEを更新]を選択します。
C. 2番目の選択では、次の項目を選択します。ON UPDATE CASCADEでNO DELETE NO ACTION
D. 最初の選択はWITH CHECKを選択してください
E. 2番目の選択では、次の項目を選択します。ON UPDATE NO ACTIONにCASCADEを削除します。
F. 2番目の選択では、次の項目を選択します。ON DELETE NO ACTION ON UPDATE NO ACTION
Answer: A,C
Explanation:
Explanation
B: We should use WITH NOCHECK as existing records in the ProductReview table must not be validated with the Product table.
C: Deletes should not be allowed, so we use ON DELETE NO ACTION.
Updates should be allowed, so we use ON DELETE NO CASCADE
NO ACTION: the Database Engine raises an error, and the update action on the row in the parent table is rolled back.
CASCADE: corresponding rows are updated in the referencing table when that row is updated in the parent table.
Note: ON DELETE { NO ACTION | CASCADE | SET NULL | SET DEFAULT }
Specifies what action happens to rows in the table that is altered, if those rows have a referential relationship and the referenced row is deleted from the parent table. The default is NO ACTION.
ON UPDATE { NO ACTION | CASCADE | SET NULL | SET DEFAULT }
Specifies what action happens to rows in the table altered when those rows have a referential relationship and the referenced row is updated in the parent table. The default is NO ACTION.
Note: You must modify the ProductReview Table to meet the following requirements:
1. The table must reference the ProductID column in the Product table
2. Existing records in the ProductReview table must not be validated with the Product table.
3. Deleting records in the Product table must not be allowed if records are referenced by the ProductReview table.
4. Changes to records in the Product table must propagate to the ProductReview table.
References: https://msdn.microsoft.com/en-us/library/ms190273.aspx
https://msdn.microsoft.com/en-us/library/ms188066.aspx

NEW QUESTION: 2
Which action is needed to edit the settings of an RF profile?
A. Remove the desired RF profile from all AP groups
B. Disable both radio networks
C. Disable custom power level settings for all APs within the group to which the profile is linked.
D. RF profiles cannot be edited. They must be removed and recreated with the desired values.
Answer: A
Explanation:
Explanation
http://www.cisco.com/c/en/us/td/docs/wireless/controller/8-0/configuration-guide/b_cg80/b_cg80_chapter_0101

NEW QUESTION: 3
The ratio of the number of linear units in the circumference of a circle to the number of square units in the
area of that circle is 2:5.What is the radius of the circle?
Answer:
Explanation:
5
Explanation/Reference:
The circumference of a circle = 2(Pi)r and the area of a circle = (Pi)r2. If the ratio of the number of linear units
in the circumference to the number of square units in the area is 2:5, then five times the circumference is
equal to twice the area:

The radius of the circle is equal to 5.