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NEW QUESTION: 1
Sie möchten Daten aus zwei Tabellen auswählen und das Ergebnis als Struktur speichern.
Die Tabelle PARTNER enthält die Felder PART_ID und KIND.
Die Tabelle CONTRACT enthält die Felder CONT_ID, CONT_TYPE und DIVISION.
Die Struktur ist wie folgt definiert
DATA: BEGIN OF wa_result,
Part_id type partner-part_id, cont_id type contract-cont_id,
Cont_type TYPE contract-cont_type,
END of wa_result,
Lt_result type table of wa_result.
How can you replace the following SELECT statement with an outer join?
SELECT part_id from partner INTO wa_result WHERE kind = 'Residential'.
SELECT cont_id from CONTRACT into wa_result-cont_id WHERE part EQ
wa_partner-part_id And DIVISION eq 'Water'.
Append wa_result to lt_result.
ENDSELECT.
If sy-subrc<>0. CLEAR wa_result-cont_id
APPEND wa_result TO lt_result. ENDIF.
ENDSELECT.
Bitte wählen Sie die richtige Antwort.
A. SELECT part_idcont_id vom Partner AS A LEFT JOIN Vertrag AS b ON a ~ part_id = b ~ part_id UND b ~ Division EQ 'Water' INTO TABLElt_result WHERE kind = 'Residential'
B. SELECT part_idcont_id vom Partner LEFT JOIN contract auf partner-part_id = contract-part_id UND contract-division EQ 'Water' INTO TABLE lt_result WHERE Art EQ 'Residential'.
C. SELECT part_idcont_id von Partner AS A LEFT JOIN Vertrag AS b ON a ~ part_id = b ~ part_id IN ENTSPRECHENDEN TABELLENFELDERN lt_result WHERE kind = 'Residential' und AND division EQ 'Water'.
D. SELECT part_idcont_id vom Partner LEFT JOIN contract auf partner-part_id = contract-part_id UND partner-kind EQ 'Residential' IN ENTSPRECHENDEN TABELLENBEREICHEN lt_result WHERE division eq
'Wasser'.
Answer: C

NEW QUESTION: 2

A. Option D
B. Option B
C. Option A
D. Option C
Answer: C

NEW QUESTION: 3
You have a variable $test that contains sub-strings divided by a dash ("-"). How can you put every sub-string into an array element easily?
A. extract($test, "-");
B. to_array($test, "-");
C. explode($test, "-");
D. explode("-", $test);
Answer: D