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NEW QUESTION: 1
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some question sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
You company has a Microsoft 365 subscription and a Virtual Desktop Infrastructure (VDI) solution.
The company's Microsoft Teams upgrade policy is set to Teams only coexistence mode.
You deploy the Microsoft Installer (MSI) package for Microsoft Teams to the VDI solution.
Several months later, users of the VDI solution report that their workstation is missing several new Microsoft Teams features.
You need to ensure that the VDI solution users can use the new Microsoft Teams features.
Solution: You run the Get-WUInstall cmdlet and specify the -AcceptAll parameter.
Does this meet the goal?
A. No
B. Yes
Answer: A

NEW QUESTION: 2
10.0.0.0/24サブネット内の奇数番号のホストから許可される標準のアクセス制御エントリはどれですか。
A. 許可10.0.0.1.0.0.0.0
B. 許可10.0.0.1.0.0.0.254
C. 許可10.0.0.0.0.0.0.1
D. 許可10.0.0.0.255.255.255.254
Answer: B
Explanation:
Explanation
Remember, for the wildcard mask, 1s are I DON'T CARE, and 0s are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum: 0001111 = 31).

The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 000 ) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a "0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all oddnumbered hosts in the 10.0.0.0/24 subnet.

NEW QUESTION: 3
You must implement an IPsec VPN on an SRX Series device using PKI certificates for authentication. As part of the implementation, you are required to ensure that the certificate submission, renewal, and retrieval processes are handled automatically from the certificate authority.
In this scenario, which statement is correct.
A. You can use SPKI to accomplish this behavior.
B. You can use CRL to accomplish this behavior.
C. You can use SCEP to accomplish this behavior.
D. You can use OCSP to accomplish this behavior.
Answer: C
Explanation:
Certificate Renewal The renewal of certificates is much the same as initial certificate enrollment except you are just replacing an old certificate (about to expire) on the VPN device with a new certificate. As with the initial certificate request, only manual renewal is supported. SCEP can be used to re-enroll local certificates automatically before they expire. Refer to Appendix D for more details.