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NEW QUESTION: 1
VMware's ESXi Hypervisor is a Type-1 hypervisor. What does this mean?
A. It should only be run in class 1 data centers with high availability.
B. It runs a conventional operating system and abstracts the guest operating system from its host system.
C. It runs directly on the host hardware to control and manage the guest operating systems.
D. It should be placed first in your data center.
Answer: C

NEW QUESTION: 2
Wireless Diagnostics incorporates Monitor Mode. Which of the following customer scenarios would Monitor Mode help with the most?
A. A customer is having trouble sending and receiving Mail on a company wireless network.
B. A customer will intermittently have a Wi-Fi connection drop. The customer cannot narrow down any specific time that it happens.
C. A customer cannot connect to any password-protected wireless networks.
D. A customer is experiencing slow speeds on a specific public Wi-Fi connection.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Use Monitor mode for intermittent issues, such as unexpectedly dropped connections and auto-join issues.
When an issue is detected, Monitor mode will automatically stop, indicate it's detected an issue, and collect information about what occurred. Information will be saved to the desktop as part of the Wireless Diagnostics report, so that you may share it with a network specialist.
Reference: https://support.apple.com/en-ap/HT202663

NEW QUESTION: 3
Given a code fragment:
StringBuilder sb = new StringBuilder ();
String h1 = "HelloWorld";
sb.append("Hello").append ("world");
if (h1 == sb.toString()) {
System.out.println("They match");
}
if (h1.equals(sb.toString())) {
System.out.println("They really match");
}
What is the result?
A. They match They really match
B. They really match
C. Nothing is printed to the screen
D. They match
Answer: C
Explanation:
Strings can not be compared with the usual <, <=, >, or >= operators, and the ==
and != operators don't compare the characters in the strings. So the first if statement fails.
Equals works fine on strings. But it does not work here.The second if-statement also fails.
TheStringBufferclass does not override the equals method so it uses the equals method of
Object.If a and b are two objects from a class which doesn't override equals, thena.equals(b) is
the same as a == b

NEW QUESTION: 4
Subscription1という名前のAzureサブスクリプションがあります。 Subscription1には、VM1という名前の仮想マシンが含まれています。
Windows 10を実行するComputer1という名前のコンピューターがあります。Computer1はインターネットに接続されています。
展示に示すように、Interface1という名前のネットワークインターフェースをVM1に追加します（[展示]ボタンをクリックします）。

Computer1から、リモートデスクトップを使用してVM1に接続しようとしましたが、接続に失敗しました。
VM1へのリモートデスクトップ接続を確立する必要があります。
最初に何をすべきですか？
A. DenyAllOutBound送信ポートルールを削除します。
B. DenyAllInBound受信ポート規則を削除します。
C. VM1を起動します。
D. ネットワークインターフェイスを接続します。
Answer: C
Explanation:
Note: Rules are processed in priority order, with lower numbers processed before higher numbers, because lower numbers have higher priority. Once traffic matches a rule, processing stops. As a result, any rules that exist with lower priorities (higher numbers) that have the same attributes as rules with higher priorities are not processed.
References: https://docs.microsoft.com/en-us/azure/virtual-network/security-overview