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NEW QUESTION: 1
Identify three ways in which the Fair Share Scheduler can be assigned.
A. zonecfg set pool=<value>
B. by creating a project and attaching a process to that project
C. zonecfg set cpu-shares=<value>
D. poolcfg
E. dispadmin
Answer: C,D,E
Explanation:
A: Resource Allocation: Zones, Pools and FSS
Example:
Then create a pool for your zone (in this example, we'll use the zones named 'habitue,'
'creator,' 'netid,' and 'linguo'): pooladm -x
pooladm -s
poolcfg -c 'create pool habitue-pool ( string pool.scheduler = "FSS" )'
poolcfg -c 'create pool creator-pool ( string pool.scheduler = "FSS" )'
poolcfg -c 'create pool linguo-pool ( string pool.scheduler = "FSS" )'
poolcfg -c 'create pool netid-pool ( string pool.scheduler = "FSS" )'
pooladm -c
B: Set the default scheduler for the system to be the FSS. # dispadmin -d FSS
D: Example: global# zonecfg -z global zonecfg:myzone> set cpu-shares=100 zonecfg:myzone> set scheduling-class=FSS zonecfg:myzone> exit

NEW QUESTION: 2
What is the purpose of the Solution Business Impact Index?
A. It is a number that identifies how sooner in the implementation roadmap should the benefits appear.
B. It is a matrix that lists the solutions and business priorities of the customer, and ranks the solutions according to the impact they generate.
C. It is an alternative to the business outcome-based sales approach.
D. It is a chart to display the importance of Cisco technologies.
Answer: B

NEW QUESTION: 3
Given the fragment:
String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
// insert code fragment here
Which code fragment when inserted at line '// insert code fragment here', enables the code to successfully change arra elements to uppercase?
A. for (int i = 0; i < 3; i++) {
for (int j=0; j < 4; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
B. for (String a[]:arra[][]) {
for (String x:a[]) {
C. toUpperCase();
}
}
D. for (int i:arra.length) {
for (String x:arra) {
arra[i].toUpperCase();
}
}
E. String[][] arra = new String[3][];
arra[0] = new String[]{"rose", "lily"};
arra[1] = new String[]{"apple", "berry","cherry","grapes"};
arra[0] = new String[]{"beans", "carrot","potato"};
for (int i = 0; i < arra.length; i++) {
for (int j=0; j < arra[i].length; j++) {
arra[i][j] = arra[i][j].toUpperCase();
}
}
Answer: B
Explanation:
Incorrect:
not A:arra.lengthis 3, but the subarrays have 2, 3 and 4 elements. Index will be out of bound.
not B: The subarrys are of different lengths.Index will be out of bound.
not D: Compile error.

NEW QUESTION: 4

A. No
B. Yes
Answer: B