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NEW QUESTION: 1

A. Disk Mirroring
B. Adaptive Query Processing
C. System Managed Access Path Protection
D. SMP Parallelism
Answer: C

NEW QUESTION: 2
Service A is a task service that sends Service B a message (2) requesting that Service B
return data back to Service A in a response message (3). Depending on the response
received. Service A may be required to send a message to Service C (4) for which it
requires no response.
Before it contacts Service B, Service A must first retrieve a list of code values from its own
database (1) and then place this data into its own memory. If it turns out that it must send a
message to Service C, then Service A must combine the data it receives from Service B
with the data from the code value list in order to create the message it sends to Service C.
If Service A is not required to invoke Service C, it can complete its task by discarding the
code values.
Service A and Service C reside in Service Inventory A.
Service B resides in Service Inventory B.

You are told that the services in Service Inventory A were designed with service contracts
based on different design standards than the services in Service Inventory B.
As a result,Service A and Service B use different data models to represent the data they need to
exchange. Therefore, Service A and Service B cannot currently communicate.
Furthermore, Service C is an agnostic service that is heavily accessed by many concurrent
service consumers. Service C frequently reaches its usage thresholds during which it is not
available and messages sent to it are not received. How can this service composition
architecture be changed to avoid these problems?
A. The Data Model Transformation pattern can be applied by establishing an intermediate
processing layer between Service A and Service B that can transform a message from one
data model to another at runtime. The Asynchronous Queuing pattern can be applied to
establish an intermediate queue between Service A and Service C so that when Service A
needs to send a message to Service C, the queue will store the message and retransmit it
to Service C until it is successfully delivered. The Service Autonomy principle can be
further applied to Service C together with the Redundant Implementation pattern to help
establish a more reliable and scalable service architecture.
B. The Data Model Transformation pattern can be applied by establishing an intermediate
processing layer between Service A and Service B that can transform a message from one
data model to another at runtime. The Intermediate Routing and Service Agent patterns
can be applied so that when Service B sends a response message, a service agent can
intercept the message and, based on its contents, either forward the message to Service A
or route the message to Service C . The Service Statelessness principle can be applied
with the help of the State Repository pattern so that Service A can write the code value
data to a state database while it is waiting for Service B to respond.
C. None of the above.
D. The Data Model Transformation pattern can be applied by establishing an intermediate
processing layer between Service A and Service B that can transform a message from one
data model to another at runtime. The Intermediate Routing and Service Agent patterns
can be applied so that when Service B sends a response message, a service agent can
intercept the message and, based on its contents, either forward the message to Service A
or route the message to Service C . The Service Autonomy principle can be further applied
to Service C together with the Redundant Implementation pattern to help establish a more
reliable and scalable service architecture.
Answer: A

NEW QUESTION: 3
Where is the Hypervisor installed?
A. Control node
B. Computer node
C. Guest operating system
D. Host operating system
Answer: B
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 4
How did Router1 acquire an IPv6 address on Ethernet0/0?
Router1# show ipv6 interface
Ethernet0/0 is up, line protocol is up
IPv6 is enabled, link-local address is FE80::A8BB:CCFF:FE00:500
No Virtual link-local address(es):
Stateless address autoconfig enabled
Global unicast address(es):
2001:DB8:A:0:A8BB:CCFF:FE00:500, subnet is 2001:DB8:A::/64
[EUI/CAL/PRE]
valid lifetime 2591961 preferred lifetime 604761
<... output omitted ...>
A. via manual configuration
B. via DHCPv6 Lite
C. via stateless autoconfiguration
D. via DHCPv6
Answer: C
Explanation:
Because Stateless address autoconfig is enabled in the show output.