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NEW QUESTION: 1
有効性をチェックしない非検証XMLプロセッサを使用して以下の属性値を読み取った結果を正しく説明しているステートメントを選択してください。 [＃x9]は＃x9を使用して表示され、[＃xA]は#xAを使用して表示され、[＃xD]は#xDを使用して表示され、[＃x20]は＃x20を使用して表示されることに注意してください。
<！ENTITY ENT "[#xA] [＃x9] data 1 [#xD] [＃xA] data 2">
Attribute = "＆ENT;"
A. Attribute = "＆ENT;"
B. Attribute = "data 1 [＃x20] data 2"
C. Attribute = "[＃x20] [＃x20] data 1 [＃x20] data 2"
D. Attribute = "[＃xA] [＃x9] data 1 [#xD] [＃xA] data 2" W Courier Newlr Z
Answer: C

NEW QUESTION: 2
Refer to the exhibit.

The report definition shown in the exhibit is for a bar chart that displays the average Duration of Process Execution for a specific process, aggregated by attr1 of my_sdt. The report has not been tuned for performance. What can an application developer do to improve performance of this report?
A. Remove the filter from the Process Execution entity and re-publish the report.
B. Create an index on the attr1 column of the table that represents the my_sdt entity in the BAM database.
C. Create an index on the Duration column of the table that represents the Process Execution entity in the BAM database.
D. Remove the filter from the my_sdt entity and re-publish the report.
Answer: B

NEW QUESTION: 3
View the exhibit and examine the structure of the EMPLOYEES table.

You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id = 100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id = 100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id and AND e.manager_id = 100
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id = 100;
Answer: A

NEW QUESTION: 4
Refer to the graphic. Two peering routers are running RIP. RTA is using RIPv1 to advertise its routes, while RTB is using RIPv2. What effect will this have on learned routes?
A. Neither RTA nor RTB are able to learn the RIP routes advertised by the peer.
B. RTB will learn the RIP route advertised by RTA, however RTA is unable to learn the route advertised by RTB.
C. RTA will learn the RIP route advertised by RTB, however RTB is unable to learn the route advertised by RTA.
D. RTA and RTB will both learn the routes advertised by RIP.
Answer: C