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NEW QUESTION: 1
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to determine the total number of customers who have either deposit accounts or loan accounts, but not both types of accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo =
B. CustNo IS NULL
C. CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT
AcctNoFROM tblLoanAcct) R
E. CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT
CustNoFROM tblLoanAcct) R
G. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN
tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT
CustNoFROM tblLoanAcct) R
I. SELECT COUNT (DISTINCT CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE
J. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT
CustNoFROM tblLoanAcct) R
K. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct
DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR
Answer: K
Explanation:
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO
FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 2
Given a log file loga.log with timestamps of the format DD/MM/YYYY:hh:mm:ss, which command filters out all log entries in the time period between 8:00 am and 8:59 am?
A. grep -E loga.log ':08:[0-9]+:[0-9]+'
B. grep loga.log ':08:[0-9]:[0-9]'
C. grep -E ':08:[00]+' loga.log
D. grep -E ':08:[09]+:[09]+' loga.log
E. grep -E ':08:[0-9]+:[0-9]+' loga.log
Answer: E

NEW QUESTION: 3
Which statement is true about internal and external LOBs?
A. A NOEXIST_DIRECTORY exception can be raised when using internal and external LOBs.
B. When using DBMS_LOB.INSTR for internal and external LOBs, DBMS_LOB.OPEN should be called for each LOB.
C. After an exception transfers program control outside a PL/SQL block, all references to open external LOBs are lost.
D. Internal and external LOBs can be written using DBMS_LOB.
E. An external LOB can be loaded into an internal LOB variable using the DBMS_LOB package.
Answer: B,C
Explanation:
Explanation/Reference:
Reference: https://docs.oracle.com/cd/E18283_01/appdev.112/e16760/d_lob.htm

NEW QUESTION: 4
Chloe would like to add an alias for one of her forms. What is one way she could do that?
A. Add a computed field named "Alias" to the form and set its value to the alias.
B. Add a "|" (pipe symbol) and the alias after the Name specified in the form properties.
C. Add a $Alias item to the form design note with the alias as its value.
D. Add the alias to the "Alias Names" section in the form properties.
Answer: B