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NEW QUESTION: 1
The INV_HISTORY table is created using the command:

The following data has been inserted into the INV_HISTORY table:

You would like to store the data belonging to the year 2006 in a single partition and issue the command:
SQL> ALTER TABLE inv_history
MERGE PARTITIONS
FOR(TO_DATE('15-feb-2006','dd-mon-yyyy')),
FOR(TO_DATE('15-apr-2006'))
INTO PARTITION sys_py;
What would be the outcome of this command?
A. It produces an error because the date values specified in the merge do not match the date values stored in the table.
B. It executes successfully, and the transition point is set to '1-apr-2006'.
C. It executes successfully, and the transition point is set to '15-apr-2006'.
D. It produces an error because the partitions specified for merging are not adjacent.
Answer: D
Explanation:
Explanation/Reference:
Explanation:

NEW QUESTION: 2
ルータのPIDとシリアル番号を表示するには、どちらのコマンドを入力する必要がありますか？ 2つ選択してください
A. バージョンを表示
B. ライセンスudiを表示
C. ライセンス機能を表示
D. ライセンスを表示
E. ライセンスステータスを表示
Answer: A,B

NEW QUESTION: 3
You create a Web page that contains the following code.
<script type="text/javascript">
var lastId = 0; </script> <div class="File">
Choose a file to upload:
<input id="File0" name="File0" type="file" /> </div> <input id="AddFile" type="button" value="Add a File" /> <input id="Submit" type="submit" value="Upload" />
You need to provide the following implementation.
Each time the AddFile button is clicked, a new div element is created.
The new div element is appended after the other file upload div elements and before the AddFile span.
Each new element has a unique identifier.
Which code segment should you use?
A. $("#AddFile").click(function () { var id = "File" + ++lastId; var item = $(".File:first").clone(true); $("input:file", item).attr({ id: id, name: id }); item.insertBefore("#AddFile");
});
B. $("#AddFile").click(function () { var id = "File" + ++lastId; $(".File:first").clone(true).attr({ id: id, name: id }).insertBefore
("#AddFile");
});
C. $("#AddFile").click(function () {
var id = "File" + ++lastId;
});
D. $("#AddFile").click(function () { var id = "File" + ++lastId; var item = $(".File:first").clone(true); $("input:file", item).attr({ id: id, name: id }); item.insertAfter("input[type=file]");
});
Answer: A