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NEW QUESTION: 1
Which of the following is TRUE?
A. When runtime column propagation is enabled, you can use output mapping on a stage to rename or drop columns
B. The DB2 Connector stage can have, at most, one input link
C. The Modify stage can keep or drop records
D. The Copy stage can be used for implicit data type conversions
Answer: A
Explanation:
Reference:https://www01.ibm.com/support/knowledgecenter/SSZJPZ_9.1.0/com.ibm.swg.im.iis.conn.oracon.usage.doc/t opics/r_runtime_column_propagation.html(Useage).

NEW QUESTION: 2
Segment routing (SR) is a protocol based on what idea to design for forwarding packets on the network?
A. Policy routing
B. Routing strategy
C. Destination routing
D. Source routing
Answer: D

NEW QUESTION: 3
Drag and Drop Question
Drag and drop the IPv4 network subnets from the left onto the correct usable host ranges on the right

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 4




While the Nexus 7010 switches are configured with vPC, the Nexus 5000 switch connections to each Nexus
7010 are configured as regular port-channels. Which statement best describes the problem affecting the port channel on N5K1?
A. The remote ends of the port-channel on N5K1 cannot use the same interface.
B. LACP is not configured to initiate negotiations.
C. N5K1 must also be configured with vPC.
D. load-balancing is not configured correctly on N5K1.
Answer: A
Explanation:
Explanation
The remote ends of the port-channel on N5K1 cannot use the same interface.
If you look at the remote ends and issue the "show interface port-channel, you will see that only one physical interface is assigned to the port channel.